Two 50\(\mu\)F parallel plate capacitors are connected in series. The combined capacitor is then connected across a 100-V battery. The charge on each plate of the capacitor is
A
5.00 x 10-5C
B
2.50 x 10-3C
C
1.25 x 10-3C
D
1.00 x 10-2C
Verified Correct Answer: B.
Physical Principles & Numerical Solution
For series, C = \(\frac{50 \times\ 50}{50 + 50}\)
C= 25\(\mu\)F
Q = CV
Q = 25 x 100 x 10-3
Q = 2.5 x 10-3C
Source: Myschool Past Questions Archive (Record #27732)