The length of mercury thread when it is at 0^\circC, 100^\circC and at an unknown temperature \(\theta\) is 25mm, 225mm and 175mm respectively. The value of \(\theta\) is
A
85.0oC
B
80.0oC
C
75.0oC
D
70.0oC
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\frac{175 - 25}{225 - 25} = \frac{x - 0}{100 - 0}\)
\(\frac{150}{200} = \frac{x}{100}\)
\(x = \frac{150 \times 100}{200}\)
= 75^\circC
Source: Myschool Past Questions Archive (Record #27692)