A ball is moving at 18ms\(^{-1}\) in a direction inclined at 60º to the horizontal. The horizontal component to its velocity is
A
9√3ms-1 ·
B
6√3ms-1 ·
C
8√3ms-1 ·
D
9ms-1 ·
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Since the angle is inclined to the horizontal,
The horizontal component of the velocity V\(_x\) = V x cos \(\theta\) = 18 x cos 60º = 9m/s
(NOTE: Cos 60º = 0.5)
Source: Myschool Past Questions Archive (Record #27584)