Calculate the temperature change when 500J of heat is supplied to 100g of water
[specific heat capacity of water = 4200JKg\(^{-1}\)k\(^{-1}\)]
A
12.1oC
B
2.1oC
C
1.2oC
D
0.1oC
Verified Correct Answer: C.
Physical Principles & Numerical Solution
\(\theta = \frac{Q}{MC}\)
\(\theta = \frac{500}{0.1 \times 4200}\) ≈ 1.2 ºC
Source: Myschool Past Questions Archive (Record #27395)