If a load of 1 kg stretches a cord by 1.2cm, what is the force constant of the cord? {g=10ms-2}
A
866Nm-1
B
833Nm-1
C
769Nm-1
D
667Nm-1
Verified Correct Answer: B.
Physical Principles & Numerical Solution
K = \(\frac{F}{e}\)
K = \(\frac{1 \times 10}{\frac{0.2}{100}}\)
K = \(\frac{10}{12} \times \frac{1000}{1}\)
Source: Myschool Past Questions Archive (Record #27386)