A simple pendulum of length 0.4m has a period of 2s. What is the period a similar pendulum of length 0.8m at the same place?
A
8s
B
4s
C
2\(\sqrt{2}s\)
D
\(\sqrt{2}s\)
Verified Correct Answer: C.
Physical Principles & Numerical Solution
T2 = \(\sqrt{\frac{L^2 \times T_1^2}{L_1}}\)
= \(\sqrt{\frac{0.8 \times 2^2}{0.4}}\)
= 2\(\sqrt{2}s\)
Source: Myschool Past Questions Archive (Record #27122)