A force of 500N1 is applied to a steel wire of cross-sectional area 0.2m2, The tensile stress is
A
2.5x104Nm-2
B
1.0x102Nm-2
C
1.0x103Nm-2
D
2.5x103Nm-2
Verified Correct Answer: D.
Physical Principles & Numerical Solution
\(Stress = \frac{Force}{Area}\)
\(Stress = \frac{500}{0.2} = 2500\)
= 2.5 x 103Nm-3
Source: Myschool Past Questions Archive (Record #26967)