A charge of 1 x \(10^{-5}\)C experiences a force of 40N at a certain point in space. What is the magnitude of the electric field intensity at the point in Newton and couloumb
A
8 x \(10^{6}\)
B
4 x \(10^{6}\)
C
3 x \(10^{-4}\)
D
2 x \(10^{-4}\)
E
5 x \(10^{-7}\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(E= \frac{F}{O}= \frac{40}{1\times10^{-5}}=4 \times10^{6}\)
Source: Myschool Past Questions Archive (Record #26329)