Given: Peak current, \( I_{\text{peak}} = 5 \, \text{A} \), Resistance, \( R = 10 \, \Omega \) Calculate the rms current: The rms current is given by: \(I_{\text{rms}} = \frac{I_{\text{peak}}}{\sqrt{2}} = \frac{5}{\sqrt{2}} \approx 3.54 \, \text{A}\) Calculate the power dissipated in the resistor: Using the rms value, the power can be calculated as: \(P = I_{\text{rms}}^2 \cdot R\) Substituting the values: \(P = \left(\frac{5}{\sqrt{2}}\right)^2 \cdot 10\) Calculating: \(P = \frac{25}{2} \cdot 10 = 125 \, \text{W}\).