An electric kettle rated 1500W boils away 0.3kg of a liquid at its boiling point every 300s. Calculate the specific latent heat of the vaporisation of the liquid
A
1.5 x \(10^6Jkg^-1\)
B
1.35 x \(10^6Jkg^-1\)
C
1.5 x \(10^5Jkg^-1\)
D
4.5 x \(10^2Jkg^-1\)
E
3 x \(10^2Jkg^-1\)
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Pt=mI; I=\(\frac{1500\times300}{0.3}=1.5\times10^6Jkg^-1\)
Source: Myschool Past Questions Archive (Record #26281)