A cell of e.m.f. 1.5V and internal resistance of 2.5Ω is connected in series with an ammeter of resistance 0.5W and a resistor of resistance of 7.0Ω. Calculate the current in the circuit.
A
0.15A
B
0.20A
C
2.10A
D
3A
E
6.6A
Verified Correct Answer: A.
Physical Principles & Numerical Solution
I =\(\frac{E}{R+r} = \frac{1.5}{2.5+0.5+7}\) = 0.15A
Source: Myschool Past Questions Archive (Record #26276)