Using the diagram above, calculate the effective capacitance of the circuit
Attached Figure / Diagram
A
1.56μf
B
3.00μF
C
3.71μF
D
9.00μF
Verified Correct Answer: A.
Physical Principles & Numerical Solution
\(C_1\) = 3\muF + 4\muF = 7\muF ( capacitance in parallel )
\(\frac{1}{ C} = \frac{ 1}{2} + \frac{1}{7} = \frac{ 7 + 2 }{14} = \frac{9}{14}\)
∴ C = \(\frac{14}{9}\) = 1.56\muF
Source: Myschool Past Questions Archive (Record #25498)