The diagram above illustrates a variation of the displacement y of a wave particle with time t. lf the velocity of wave is 250ms-1, calculate the distance between two successive particles which are in phase
Attached Figure / Diagram
A
20m
B
2.5m
C
3.0m
D
5.0m
E
50.0m
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Time to complete one circle = 0.02secs
But, v = f\(\lambda\)
f = \(\frac{1}{f}\) = \(\frac{1}{0.02}\) = 50Hz
\(\lambda\) = \(\frac{250}{50}\) = 5m.
Source: Myschool Past Questions Archive (Record #25237)