ai. To find all the elements in the set M, we have to solve the inequality. 2n - 3 ≤ 37 2n = 37 + 3 = 40. 2n ≤ 40 n ≤ \(\frac{40}{2}\) n ≤ 20 so, the set M contains all positive numbers n such that n is less than or equal to 20 Therefore, set M elements are {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20} (α) Pr(multiple of 3) = \(\frac{multiples of 3}{ Total number of element in M}\) But the multiples of 3 in set M are = {3, 6, 9, 12, 15, 18} = 6 ஃ Pr(multiples of 3) = \(\frac{6}{20} = \frac{3}{10}\) (β) Pr( factors of 10) = \(\frac{№ of factors of 10}{ Total № of set M elements}\) factors of 10 in set M = { 1, 2, 5, and 10} = 4 ஃ Pr( factors of 10) = \(\frac{4}{20} = \frac{1}{5}\) bi. Let the total amount shared = y Gapson's age = \(\frac{3}{2}\times Kontor's age\). Since kontor is 20yrs old then Gapson's age = \(\frac{3}{2}\times20\) = 30years. sharing ratio = 20 : 30 = 2 : 3 total ratio = 2 + 3 = 5 Since Kontor received Le200,000 \(\frac{2}{5} \times y\) = 200,000 \(\frac{2y}{5} = 200,000\) cross multiplying, we have 2y = 5 x 200,000 = 1000,000 y = \(\frac{1000,000}{2}\) = 500,000. ஃ Total amount shared = Le500,000. ii. Gapson's share = Total - kontor's share = 500,000 - 200,000 = Le300,000.