A converging lens of focal length 5cm forms a virtual image which is 10cm from the lens. How far from the lens is the object?
A
2.0cm
B
3.3cm
C
5.0cm
D
10.0cm
E
15.0cm
Verified Correct Answer: B.
Physical Principles & Numerical Solution
\(f = \frac{uv}{u+v}\)
\(5 = \frac{-10u}{-10+u}\)
\(50 + 5u = -10u\)
\(50 = -10u - 5u\)
\(u = \frac{50}{-15}\)
u= -3.3cm
Source: Myschool Past Questions Archive (Record #25230)