A rocket is launched from the surface of the earth. If the radius of the earth is 6.4 x 106m and the acceleration of free fall due to gravity is 1Oms-1 calculate the escape velocity of the rocket.
A
2.53 x 104ms-1
B
1.13 x 104ms
C
8.00 x 103ms-1
D
4.23 x 103ms-1
E
6.41 x 104ms-1
Verified Correct Answer: B.
Physical Principles & Numerical Solution
V = √2gR
V = √2 x 10 x 6.4 x 102
1.13 x 104ms
Source: Myschool Past Questions Archive (Record #25202)