A capacitor of capacitance 25\muF is connected to an a.c. power source of frequency 200 Hz. Calculate the reactance of the capacitor
A
0.01
B
0.02
C
50.00
D
100.00
E
200.00.
Verified Correct Answer: D.
Physical Principles & Numerical Solution
To calculate the reactance of a capacitor, we use the formula:
\(X_C = \frac{1}{2 \pi f C}\)
Given: C = 25\(\mu\)F = 25 \(\times 10^{-6}\), F = 200 Hz
Substituting the values into the formula, we approximate \( \pi \) as 10:
\(X_C = \frac{1}{2 \times 10 \times 200 \times (25 \times 10^{-6})}\)
Calculating this: \(X_C = \frac{1}{2 \times 10 \times 200 \times 25 \times 10^{-6}} = \frac{1}{0.01} = 100 \Omega\)
Thus, the capacitive reactance is: 100\( \Omega\)
Source: Myschool Past Questions Archive (Record #25094)