A particle of charge 5C moves perpendicularly to a magnetic Held of magnitude C.01 T. If the velocity of the charge is 1.5ms'2, calculate the magnitude of the force exerted on the particle
A
0.050 N
B
0.075N
C
0.0300N
D
3.300N
E
0.000N
Verified Correct Answer: B.
Physical Principles & Numerical Solution
F = eV = 0.01 x 5 x 1.5 = 0.075N
Source: Myschool Past Questions Archive (Record #25033)