A body of mass m = 0.5 kg is suspended by a string and pulled by a horizontal force of 12N as shown in the diagram. Calculate the tension T in the String if the body is in equilibrium. [Take g as 10ms\(^{-1}\)]
Attached Figure / Diagram
A
7.0
B
10.9
C
12.5
D
13.0
E
17.0
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Mg = 5N
T\(_2\) = 5\(^2\) + 12\(^2\) = 13N
Source: Myschool Past Questions Archive (Record #24998)