Using the lens formula: Using the lenses formula and applying the real-is-positive convention \(\frac{1}{v}\) + \(\frac{1}{u}\) = \(\frac{1}{f}\) f = -10cm for diverging lens, v = 5cm real image \(\frac{1}{u}\) = \(\frac{1}{f}\) - \(\frac{1}{v}\) \(\frac{1}{u}\) = \(\frac{1}{-10}\) - \(\frac{1}{5}\) \(\frac{1}{u}\) = \(\frac{-1 - 2}{10}\) = \(\frac{-3}{10}\) U = \(\frac{10}{-3}\) = - 3.33cm The negative sign indicates that the object is on the same side as the incoming light.