A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.
A
0.15 A
B
0.20 A
C
0.60A
D
3.00A
E
6.67 A.
Verified Correct Answer: A.
Physical Principles & Numerical Solution
I = E/R + r = 1.5/2.5 + 0.5 + 7 = 0.15
Source: Myschool Past Questions Archive (Record #24154)