A charge of 1.0 x 10-5 Coulombs experience force of 40N at a certain point in space. What is the electric field intensity?
A
8.00 x 106NC-1
B
4.00 x 106NC-1
C
4.00 x 10-4NC-1
D
2.00 x 10-4NC-1
E
2.50 x 10-1NC-1
Verified Correct Answer: B.
Physical Principles & Numerical Solution
F = qE; E = F/q = 40/(1.0 x 10-5) = 4.0 x 106
Source: Myschool Past Questions Archive (Record #24148)