The sum of 2 \(\frac{1}{6}\) and 2\(\frac{7}{12}\) = \(\frac{13}{6}\) + \(\frac{31}{12}\) = \(\frac{13 \times 2 + 31}{12}\) = \(\frac{26 + 31}{12}\) = \(\frac{57}{12}\) What should be subtracted from \(\frac{57}{12}\) to give 3\(\frac{1}{4}\) \(\frac{57}{12}\) - y = 3\(\frac{1}{4}\) : y = \(\frac{57}{12}\) - 3\(\frac{1}{4}\) = \(\frac{57}{12}\) - \(\frac{13}{4}\) y = \(\frac{57 - 3 \times 13}{12}\) = \(\frac{57 - 39}{12}\) y = \(\frac{18}{12}\) y = \(\frac{3}{2}\) or 1\(\frac{1}{2}\)