In the circuit above, three resistors, 2\Omega, 4\Omega and 12\Omega are connected in parallel and a 12V battery is connected across the combination. The current flowing through the 12\Omega resistors is
Attached Figure / Diagram
A
14.4 A
B
1.0 A
C
3.2 A
D
9.6 A
Verified Correct Answer: B.
Physical Principles & Numerical Solution
I = \(\frac{V}{R}\) from Ohm's law
I = \(\frac{12}{12}\) = 1A.
Source: Myschool Past Questions Archive (Record #14552)