The pressure of two moles of an ideal gas at a temperature of 27 ^\circC and volume 10\(^-2\)m\(^3\) is?
[R = 8.313 J mol\(^{-1}\)K\(^{-1}\)]
A
4.99 x 105 Nm-2
B
9.80 x 103 Nm-2
C
4.98 x 103 Nm-2
D
9.80 x 105 Nm-2
Verified Correct Answer: A.
Physical Principles & Numerical Solution
PV = nRT
∴ P = \(\frac{\text{nRT}}{\text{V}}\)
P = \(\frac{2 \times 8.313 \times 300}{10^{-2}}\)
= 4.987 x 10\(^5\) Nm\(^{-2}\)
Source: Myschool Past Questions Archive (Record #14500)