During the nuclear reaction described by
\(^{235}_{92}\)W → \(^{235}_{93}\)X → \(^{231}_{91}\)Y
The particles emitted are respectively
A
α and α
B
α and β
C
β and β
D
β and α
Verified Correct Answer: D.
Physical Principles & Numerical Solution
The decay process illustrated above shows that the lost \beta -particle to decay to the X by increase its atomic number ( from 92 to 93) and leaving the mass no. unaffected. There after, x decayed by -\alpha emission to give Y, by decreasing the mass no. by 2 ( from 93 to 91).
Thus , the emission is \beta and \alpha particles respectively
Source: Myschool Past Questions Archive (Record #14475)