Three similar cells each of e.m.f 2 v and internal resistance 2Ω are connected in parallel, the total e.m.f and total internal resistance are respectively
A
6 v, 6.0Ω
B
2 v, 0.7Ω
C
2 v, 6.0Ω
D
6 v, 0.7Ω
Verified Correct Answer: B.
Physical Principles & Numerical Solution
Total energy in parred connection is equal to emt of one cell, = 2v but total internal resistance is given by
(1)/r = (1)/r1 + (1)/r2 + (1)/r3 = (1)/2 + (1)/2 + (1)/2 = (3)/2
∴ r = (2)/3 = 0.67Ω
Source: Myschool Past Questions Archive (Record #14443)