Two balls, X and Y, weighing 5 g and 50 kg respectively, were thrown up vertically at the same time with a velocity of 100 ms\(^{-1}\). How will their positions be one second later?
A
X and Y will be 500 m from each other
B
Y will be 500 m ahead of X
C
X will be 500 m ahead of Y
D
X and Y both be 500 m from the point of throw
Verified Correct Answer: D.
Physical Principles & Numerical Solution
V\(^2\) = U\(^2\) - 2gS
0 = 100\(^2\) - 2 x 10 x S = 10000 - 20S
S = \(\frac{10000}{20}\) = 500m
Which is independent of mass. The two bodies were acted upon by the same retarding force of gravity, which is independent of the mass of the body; therefore, both will be 500 m from the point of throw.
Source: Myschool Past Questions Archive (Record #14350)