The radioisotope \( ^{235}_{92}U \) decays by emitting two alpha particles, three beta particles and a gamma ray. What is the mass and atomic number of the resulting element?
A
215 and 88
B
91 and 227
C
227 and 91
D
92 and 238
E
No correct option
Verified Correct Answer: C.
Physical Principles & Numerical Solution
- Alpha radiation consists of helium- He\(^{4}_{2}\)
2 Alpha decay --> 2 X He\(^{4}_{2}\) = Element\(^{8}_{4}\)
- Beta particles are high energy electrons- e\(^{0}_{-1}\)
3 Beta particles --> 3 X e\(^{0}_{-1}\) = Element\(^{0}_{-3}\)
- Gamma rays are waves of electromagnetic energy, or photons.
the mass and atomic number of the resulting element = U\(^{235}_{92}\) - Elements( \(^{8}_{4}\) + \(^{0}_{-3}\) )
--> Element\(^{227}_{91}\)
Source: Official Exam / Past Question Archive