The figure above shows three capacitors, 2μF, 3μF and 6μF connected in series. If the p.d across the system is 12V, the p.d, across the 6μF capacitor is
Attached Figure / Diagram
A
4V
B
12V
C
2V
D
6V
Verified Correct Answer: C.
Physical Principles & Numerical Solution
The effective capacitance in the circuit is given by:
1/C = 1/2 + 1/3 + 1/6 = 6/6
therefore C = 1μF or
1.0 x 10-6F.
Since C = Q/V, its implies that the charges Q, flowing in the circuit is given by Q = CV
= 1.0 x 10-6 x 12
= 12.0 x 10-6 Coulomb.
∴ P.d across the 6μF,
V = Q/C = 12.0 x 10-66.0 x 10-6F
= 2.0 volts
Source: Myschool Past Questions Archive (Record #14280)