\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2X \)
In the reaction above, X is
A
electron
B
proton
C
neutrino
D
neutron
Verified Correct Answer: D.
Physical Principles & Numerical Solution
\( ^{235} _{92}U + ^1 _0n → ^{144} _{56}Ba + ^{90} _{36}Kr +2^1_0X \)
In the reaction above, balancing the left with the right shows that X is a neutron
Source: Myschool Past Questions Archive (Record #14277)