Three numbers, x, y and z are connected by the relationships y = \(\frac{4x}{9}\) + 1. If x = 99, Find z = \(\frac{4y}{9}\) + 1
A
6\(\frac{1}{3}\)
B
20
C
21
D
176\(\frac{4}{9}\)
E
None of the above
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
y = \(\frac{4x}{9}\) + 1, z = \(\frac{4y}{9}\) + 1, z = \(\frac{4}{9}\)(\(\frac{4}{9}\) x + 1) + 1
= [\(\frac{4}{9}\)(\(\frac{4}{9}\)(99) + 1]
= \(\frac{4}{9}\)(45) + 1
= 21
Source: WAEC / JAMB / NECO Classroom Archive (Record #32622)