What fraction must be subtracted from the sum of \(2\frac{1}{6}\) and \(2\frac{7}{12}\) to give \(3\frac{1}{4}\)?
A
\(\frac{1}{3}\)
B
\(\frac{1}{2}\)
C
\(1\frac{1}{6}\)
D
\(1\frac{1}{2}\)
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
\(2\frac{1}{6} + 2\frac{7}{12}\)
= \(\frac{13}{6} + \frac{31}{12}\)
= \(\frac{26 + 31}{12}\)
= \(\frac{57}{12} = \frac{19}{4}\)
\(\frac{19}{4} - 3\frac{1}{4}\)
= \(\frac{19}{4} - \frac{13}{4}\)
= \(\frac{6}{4}\)
= \(1\frac{1}{2}\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #26428)