A circuit has an area of 0.4m2 and consists of 50 loops of wire. If the loops are twisted and allowed to rotate at a constant angular velocity of 10 rad s-1 in a uniform magnetic field of 0.4T, the amplitude of the induced voltage is
A
8V
B
16V
C
20V
D
80V
Verified Correct Answer: D.
Physical Principles & Numerical Solution
The induced voltage \(\epsilon\) in a coil = N* B* A * \(\omega\)
where: N = number of loops (50 loops),B = magnetic field strength (0.4 T),A = area of the loop (0.4 m\(^2\)),\(\omega\) = angular velocity (10 rad/s)
\(\epsilon\) in a coil = N* B* A * \(\omega\) = 50 x 0.4 x 0.4 x 10 = 80V
Therefore, the amplitude of the induced voltage is 80V
Source: Myschool Past Questions Archive (Record #12750)