\(^{23}_{11}\)Na + X → \(^{20}_9\)F + \(^4_2\)He
What particle is X in the reaction above?
A
Alpha
B
Beta
C
Neurons
D
Gamma
Verified Correct Answer: C.
Physical Principles & Numerical Solution
The particle in the reaction is a neutron
\(^{23}_{11}\)Na + \(^1_0\)n → \(^{20}_9\)F + \(^4_2\)He
Source: Myschool Past Questions Archive (Record #12253)