\(\sqrt{75} - \sqrt{12} + \sqrt{27} = y\sqrt{3}\) Simplify each term: - \(\sqrt{75} = \sqrt{25 \times 3} = 5\sqrt{3}\) - \(\sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}\) - \(\sqrt{27} = \sqrt{9 \times 3} = 3\sqrt{3}\) Substitute: \(5\sqrt{3} - 2\sqrt{3} + 3\sqrt{3} = y\sqrt{3}\) Combine like terms: \((5 - 2 + 3)\sqrt{3} = y\sqrt{3}\) \(6\sqrt{3} = y\sqrt{3}\) Thus, y = 6