\(3\sqrt{12} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\) = \(3\sqrt{4\times3} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\) = \(6\sqrt{3} + 10\sqrt{3} - \frac{6}{\sqrt{3}}\) treating like a fraction, then = \(\frac{18 + 30 - 6}{\sqrt{3}}\) = \(\frac{42}{\sqrt{3}}\) rationalizing = \(14\sqrt{3}\)