In the a.c circuit above, the current value is
Attached Figure / Diagram
A
0.58 A
B
3.00 A
C
4.00 A
D
6.67 A
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Impedance Z = \(\sqrt{R^2 + X^2}\)
= \(\sqrt{(30)^2 + (40)^2}\)
∴ Z = \(\sqrt{2500}\) = 50\(\Omega\)
But current I = \(\frac{V}{Z}\) = \(\frac{200}{50}\) = 4.00 A
Source: Myschool Past Questions Archive (Record #11745)