In the diagram above, the values of V1 and V2 are respectively
Attached Figure / Diagram
A
1V and 1/3V
B
1/3V and 1V
C
1/3V and 2/3V
D
1V and 2/3V
Verified Correct Answer: D.
Physical Principles & Numerical Solution
Effective resistance in the circuit
= 3 + 2 + 1 = 6\Omega
Current through the I = \(\frac{E}{(R+r)}\)
∴ I = \(\frac{2}{6}\)
=> V1 = I x R1 = \(\frac{2}{6}\times\frac{3}{1}\) = 1V
= V2 = I x R2 = \(\frac{2}{6}\times\frac{2}{1}\) = \(\frac{2}{3}\)V
∴ we have 1V and \(\frac{2}{3}\)V
Source: Myschool Past Questions Archive (Record #11737)