The diagram above shows two capacitors P and Q of capacitance 5\muF and 10\muF. Find the charges stored in P and Q respectively
Attached Figure / Diagram
A
2μC and 4μC
B
4μC and 2μC
C
100μC and 200μC
D
200μC and 100μC
Verified Correct Answer: C.
Physical Principles & Numerical Solution
Since capacitance C = Q/V, => Q = CV
∴ Qp = 5 x 10\(^{-6}\) x 20
= 100 x 10\(^{-6}\) or 100\muC
Qp = 10 x 10\(^{-6}\) x 20
= 200 x 10\(^{-6}\) or 200\muC
Correct option 100\muC and 200\muC
Source: Myschool Past Questions Archive (Record #11721)