A student is at a height 4m above the ground during a thunderstorm. Given that the potential difference between the thundercloud and the ground is 10\(^7\)V, the electric field created by the storm is
A
2.0 x 10\(^6\) NC\(^{-1}\)
B
2.5 x 10\(^6\) NC\(^{-1}\)
C
1.0 x 10\(^7\) NC\(^{-1}\)
D
4.0 x 10\(^7\) NC\(^{-1}\)
Verified Correct Answer: B.
Physical Principles & Numerical Solution
E = \(\frac{V}{d}\)
E is the electric field (in volts per meter, V/m),
V is the potential difference (in volts, V),
d is the distance between the two points (in meters, m)
Given: Potential difference V = 10\(^7\)
Height d = 4m
That is, E = \(\frac{10^7}{4} = 2.5\times 10^6 NC^{-1}\)
Source: Myschool Past Questions Archive (Record #7286)