An electric generator with a power output of 3.0KW at a voltage of 1.5KV distributes power along cables of resistance 20.0Ω. The power loss in the cables is
A
80.0W
B
40.0W
C
10.0W
D
0.1W
Verified Correct Answer: A.
Physical Principles & Numerical Solution
Power input = 3KW = 3000W
Voltage = 1.5KV = 1500V
Current (I) = P/V = 3000/1500 = 2Amps.
∴ Power loss in the cables = I2R
= 2 x 2 x 20
= 80W
Source: Myschool Past Questions Archive (Record #1435)