Solve for k in the equation \(\frac{1}{8}^{k+2}\) = 1
A
2
B
-4
C
-2
D
4
Verified Correct Answer: C.
Step-by-Step Mathematical Solution
\((8^{-1})^{k+2}\) = \((8^{0})\)
base 8 cancel out on both sides
-1(k+2) = 0
-k -2 = 0
: k = -2
Source: WAEC / JAMB / NECO Classroom Archive (Record #64147)