Divide the LCM of 15abc and 20a\(^2\)bc by their HCF
A
10a
B
12a
C
5abc
D
12a2bc
E
60a2bc
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
LCM of 15abc and 20a\(^2\)bc = 60a\(^2\)bc
Factors of 15abc = 1, 3, 5,15, a, b, c
and of 20a\(^2\)bc = 1, 2, 4, 5, 10, 20, a, b, c
HCF of 15abc and 20a\(^2\)bc = 5abc
→ LCM \div HCF = 60a\(^2\)bc \div 5abc
= 12a
Source: WAEC / JAMB / NECO Classroom Archive (Record #42299)