The area of a triangle given two sides and the included angle = \(\frac{1}{2}\) x a x b x Sin\(\theta\) a = b = 8cm \(\theta\) = 60º Area = \(\frac{1}{2}\) x 8 x 8 x Sin 60º = \(\frac{1}{2}\) x 64 x \(\frac{\sqrt{3}}{2}\) ( Sin 60º = \(\frac{\sqrt{3}}{2}\) ) = \(\frac{64\sqrt{3}}{4}\) = 16\(\sqrt{3}cm^2\)