Find ∫(sin x + 2)dx
A
cos x + x2 + K
B
cos x 2x + K
C
-cos x + x2 + K
D
-cos x + 2x + K
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
Source: Myschool Past Questions Archive (Record #10307)