x = (2+3t)(5t-4) Let u = 2+3t ∴ \(\frac{\text{du}}{\text{dt}}\) = 3 and v = 5t-4 ∴ \(\frac{\text{dv}}{\text{dt}}\) = 5 dx/dt = \(\frac{\text{Vdu}}{\text{dt}}\) + \(\frac{\text{Udv}}{\text{dt}}\) = (5t-4)3 + (2+3t)5 = 15t - 12 + 10 + 15t = 30t - 2 = 30 x \(\frac{4}{5}\) - 2 = 24 - 2 = 22