\(P=\left[\begin{array}{cc}x+3 & x+2\\ x+1 & x-1\end{array}\right]\) evaluate x if |P| = -10 (x+3)(x-1) - {(x+1)(x+2)} = -10 x2 - x + 3x - 3 - {x2 + 2x + x + 2} = -10 x2 + 2x - 3 - {x2 + 3x + 2} = -10 -x - 5 = -10 -5 + 10 = x 5 = x ∴x = 5