In the parallelogram PQRS, PE is perpendicular to QR. Find the area of the parallelogram.
Attached Figure / Diagram
A
60cm2
B
65cm2
C
72cm2
D
132cm2
E
156cm2
Verified Correct Answer: D.
Step-by-Step Mathematical Solution
By Pythagoras, PE\(^2\) = 12\(^2\) - 5\(^2\)
= 144 - 25 = 119
h = PE\(^2\) = \sqrt119 = 10.9 ≈ 11cm,
Area of 11gm = b x h
QR = b =(5 + 7)cm = 12cm
area = 12 x 11
= 132cm\(^2\)
Source: WAEC / JAMB / NECO Classroom Archive (Record #32739)