If log\(_{10}\)2 = 0.3010 and log\(_{10}\)7 = 0.8451, evaluate log\(_{10}\)280
A
3.4471
B
2.4471
C
1.4471
D
1.4071
Verified Correct Answer: B.
Step-by-Step Mathematical Solution
Log 2 = 0.3010, Log 7 = 0.8451
∴Log 280 = Log 28 x 10
= Log 7x4x10
=Log7 + Log4 + Log10
= Log7 + Log2\(^2\) + Log10
= Log7 + 2Log2 + Log10
= 0.8451 + 2(0.3010) + 1
= 0.8451 + 0.6020 + 1
= 2.4471
Source: Myschool Past Questions Archive (Record #9310)